Bila sobat mau berusaha mendapatkan cara mengerjakan atas soal (m⁻² + m⁻¹ + m°) : (m⁻¹ + m° + m) =========================== gunakan cara! jangan ngasal ==========..., maka kamu sudah ada di situs yang benar.
Laman ini punya 2 jawaban atas (m⁻² + m⁻¹ + m°) : (m⁻¹ + m° + m) =========================== gunakan cara! jangan ngasal ==========.... Monggo lihat jawaban selengkapnya di bawah:
(m⁻² + M⁻¹ + M°) : (m⁻¹ + M° + M)
===========================
gunakan Cara!
jangan Ngasal
===================
maaf :D
Jawaban: #1: [tex] \sf( m^ - 2 + m^ - 1 + m^0 ) \div ( m^ - 1 + m^0 + m)[/tex]
[tex] \sf = ( \frac1 m^2 + \frac1m + 1) \div ( \frac1m + 1 + m)[/tex]
[tex] \sf = ( \frac1 m^2 + \frac m m^2 + \frac m^2 m^2 ) \div ( \frac1m + \fracmm + \frac m^2 m )[/tex]
[tex] \sf = ( \frac1 + m + m^2 m^2 ) \div ( \frac1 + m + m^2 m )[/tex]
[tex] \sf = (\frac1 + m + m^2 m^2 ) \times ( \fracm1 + m + m^2 )[/tex]
[tex]\sf = (\frac \cancel1 + m + m^2 m^2 ) \times ( \fracm \cancel1 + m + m^2 )[/tex]
[tex] \sf = \frac1 m^2 \times \fracm1 [/tex]
[tex] \sf = \frac1 \times m m^2 \times 1 [/tex]
[tex] \sf = \fracm m^2 [/tex]
[tex] \sf = m \div m^2 [/tex]
[tex] = \sf m^ - 1 [/tex]
[tex] \sf = \frac1m [/tex]
Cmiiw
Jawaban: #2:Penjelasan dengan langkah-langkah:
(m⁻² + m⁻¹ + m°) : (m⁻¹ + m° + m)
[tex] = \sf \frac m^ - 2 + m^ - 1 + m^0 m^ - 1 + m^0 + m [/tex]
[tex] = \sf \frac \frac1 m^2 + \frac1m + 1 \frac1m + 1 + m [/tex]
[tex] = \sf\frac \frac1 m^2 + \fracmm ^2 + \frac m^2 m^2 \frac1m + \fracmm + \frac m^2 m [/tex]
[tex] = \sf \frac1 + m + m^2 m^2 \times \fracm1 + m + m^2 [/tex]
[tex] = \sf\fracm(1 + m+ m^2) m^2 (1 + m + m^2 ) [/tex]
[tex] = \sf \fracm m^2 [/tex]
[tex] = \sf \frac1m [/tex]
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Gimana? Sudah dapat cara menjawab mengenai "(m⁻² + m⁻¹ + m°) : (m⁻¹ + m° + m) =========================== gunakan cara! jangan ngasal ==========..." kan? Diharapkan solusi di atas dapat membantu pengerjaan pertanyaan kamu.